Discussion:
Does a bound electron have a magnetic dipole?
chemguy
2019-02-28 00:59:08 UTC
The four quantum numbers (n, L, mL, ms) are well defined in the literature.
Where; ms is magnetic moment associated with spin; ms = ±½ (spin up, spin down)

It is reasonable to assume that the rotation of a bound electron may set up a magnetic dipole. If a magnetic dipole does exist then the magnetic moment “associated with orbit” (mn) may have two possible values;
mn = ±½

Where;
mn = -½ represents “dipole north”
mn = +½ represents “dipole south”

Does a bound electron have orbital magnetic moment?

Reference; http://newstuff77.weebly.com page 01 The Pyramid Periodic Table
Thomas 'PointedEars' Lahn
2019-03-04 21:43:34 UTC
Post by chemguy
The four quantum numbers (n, L, mL, ms) are well defined in the literature.
Where; ms is magnetic moment associated with spin; ms = ±½ (spin up, spin down)
One usually writes m_L and m_s, otherwise that is correct.
Post by chemguy
It is reasonable to assume that the rotation of a bound electron may set up a magnetic dipole.
Not necessarily. However, it is not reasonable to assume that there is not
a magnetic dipole in the first place, because a proper interpretation of the
well-confirmed Maxwell equation ∇⃗ · B⃗ = 0 (the divergence of the magnetic
field is zero) is „magnetic field lines are closed“ which means that there
are no magnetic monopoles (by contrast to the electric field).
--
PointedEars

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Thomas 'PointedEars' Lahn
2019-03-04 21:52:53 UTC
Post by Thomas 'PointedEars' Lahn
Post by chemguy
The four quantum numbers (n, L, mL, ms) are well defined in the literature.
Where; ms is magnetic moment associated with spin; ms = ±½ (spin up, spin down)
One usually writes m_L and m_s, otherwise that is correct.
Correction: m_s parametrizes intrinsic angular momentum. The magnetic
momentum is caused by the spin and orbital angular momentum states instead.
--
PointedEars

Please do not cc me. / Bitte keine Kopien per E-Mail.
m***@gmail.com
2019-06-23 06:47:58 UTC
Post by chemguy
The four quantum numbers (n, L, mL, ms) are well defined in the literature.
Where; ms is magnetic moment associated with spin; ms = ±½ (spin up, spin down)
It is reasonable to assume that the rotation of a bound electron may set up a magnetic dipole. If a magnetic dipole does exist then the magnetic moment “associated with orbit” (mn) may have two possible values;
mn = ±½
Where;
mn = -½ represents “dipole north”
mn = +½ represents “dipole south”
Does a bound electron have orbital magnetic moment?
Reference; http://newstuff77.weebly.com page 01 The Pyramid Periodic Table
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it seems reasonable == so having a dipole
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Y.P
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